# How do you find the discriminant of #x^2-12x+4=0#?

##### 1 Answer

Dec 1, 2016

#### Answer:

#### Explanation:

#x^2-12x+4 = 0#

is in the form:

#ax^2+bx+c = 0#

with

It has discriminant

#Delta = b^2-4ac = (-12)^2-4(1)(4) = 144-16 = 128 = 2*8^2#

Since

We can find the roots using the quadratic formula:

#x = (-b+-sqrt(b^2-4ac))/(2a)#

#color(white)(x) = (-b+-sqrt(Delta))/(2a)#

#color(white)(x) = (12+-sqrt(2*8^2))/2#

#color(white)(x) = (12+-8sqrt(2))/2#

#color(white)(x) = 6+-4sqrt(2)#