Question

How do you find the domain and range for `f(x) = 1/(1+x^2)`?

Answer 1

Domain: `RR`

Range: `0<x≤1`

Explanation:

The domain of the function is all of `RR` as no value of `x` causes the function to be undefined.

The range is `0<x≤1`. For `x=0` the function takes the value `1` and for all `x→±∞` the function is decreasing and tends to `0`.