How do you find the domain and range for #y =sqrt(x-1)#?

1 Answer
Jun 21, 2015

Answer:

With radical functions, we know that both the expression under the root and the outcome must be non-negative.

Explanation:

So #x-1>=0->x>=1#
There is no upper limit to #x# so the domain is:
#1<=x< oo#

As for the range:
#y# must always be #>=0#
Since there is no upper limit to #x#, there is also no upper limit to #y#
#0<=y< oo#
graph{sqrt(x-1) [-16.12, 48.84, -16.18, 16.3]}