# How do you find the domain and range for y =sqrt(x-1)?

##### 1 Answer
Jun 21, 2015

With radical functions, we know that both the expression under the root and the outcome must be non-negative.

#### Explanation:

So $x - 1 \ge 0 \to x \ge 1$
There is no upper limit to $x$ so the domain is:
$1 \le x < \infty$

As for the range:
$y$ must always be $\ge 0$
Since there is no upper limit to $x$, there is also no upper limit to $y$
$0 \le y < \infty$
graph{sqrt(x-1) [-16.12, 48.84, -16.18, 16.3]}