How do you find the domain and range for #y = (x-5)^2#?

1 Answer
Apr 16, 2018

Answer:

See the explanation given below :-

Explanation:

Since this function is defined for all Real numbers , so the domain of the function is

#D_f = x# #ϵ# # R# ; where #R# is the set of all Real numbers.

And since this is a Square function so its value can go from #0# to #∞# : -

#:.# the range of the function #R_f = [0,∞)#

The graph of the function is given below :-

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