# How do you find the domain and range of 2 / x^2?

Dec 30, 2017

Domain: $x \in \mathbb{R} , x \ne 0$.
Range: $y > 0$.
The only value that you cannot substitute into $y = \frac{2}{x} ^ 2$ is $x = 0$, so the domain is all reals except 0. Domain: $x \in \mathbb{R} , x \ne 0$.
The range of $y = \frac{2}{x} ^ 2$ is $y > 0$. Since we're squaring $x$ we will only get positive values and it's not possible to get 0 when the numerator is a constant 2.