How do you find the domain and range of #(8x-48)/(x^2-13x+42)#?

1 Answer
Mar 23, 2016

Answer:

Domain (x) are all real numbers of x except #x=7#
Range(y) are all real numbers except for #x=7#

Explanation:

#y=(8x-48)/(x^2-13x+42) = (8*(x-6))/((x-7)*(x-6)) =8/(x-7)#
Domain (x) is all real numbers of x except #x=7#. As at x=7 denominator will be 0 and the function will not exist.
Range(y) is all real numbers except for #x=7#