# How do you find the domain and range of (8x-48)/(x^2-13x+42)?

Mar 23, 2016

Domain (x) are all real numbers of x except $x = 7$
Range(y) are all real numbers except for $x = 7$
$y = \frac{8 x - 48}{{x}^{2} - 13 x + 42} = \frac{8 \cdot \left(x - 6\right)}{\left(x - 7\right) \cdot \left(x - 6\right)} = \frac{8}{x - 7}$
Domain (x) is all real numbers of x except $x = 7$. As at x=7 denominator will be 0 and the function will not exist.
Range(y) is all real numbers except for $x = 7$