Question

How do you find the domain and range of `(8x-48)/(x^2-13x+42)`?

Answer 1

Domain (x) are all real numbers of x except `x=7`
Range(y) are all real numbers except for `x=7`

Explanation:

`y=(8x-48)/(x^2-13x+42) = (8*(x-6))/((x-7)*(x-6)) =8/(x-7)`
Domain (x) is all real numbers of x except `x=7`. As at x=7 denominator will be 0 and the function will not exist.
Range(y) is all real numbers except for `x=7`