How do you find the domain and range of #f(x)= (2x^2+7x-15) / (x+5)#?

1 Answer
May 17, 2018

Answer:

#x inRR,y inRR#

Explanation:

#"factorise and simplify by cancelling"#

#f(x)=((2x-3)cancel((x+5)))/cancel(x+5)=2x-3#

#f(x)" simplifies to a linear expression which has no "#
#"restrictions on it's domain and hence no restrictions"#
#"on it's range"#

#rArr"domain "x inRR#

#rArr"range "y inRR#
graph{(2x^2+7x-15)/(x+5) [-10, 10, -5, 5]}