# How do you find the domain and range of f(x)=-4+sqrt(x+3)?

##### 1 Answer
Dec 29, 2017

Suppose,$y = f \left(x\right) = - 4 + \sqrt{x + 3}$

*Here,
$f \left(x\right) = - 4 + \sqrt{x + 3}$
If we substitute the value of $x$ less than$- 3$,the value of equation will be indefinable. *

So,Domain$\mathbb{R} = \left\{x : x \in \mathbb{R} , x \ge \left(- 3\right)\right\}$

Again, for the value of domain set, the value of range set will be greater than or equal -4

So,Range$\mathbb{R} = \left\{y : y \in \mathbb{R} , y \ge \left(- 4\right)\right\}$$\textcolor{b r o w n}{\left(A n s .\right)}$