How do you find the domain and range of #f(x)=-4+sqrt(x+3)#?

1 Answer
Dec 29, 2017

Suppose,#y=f(x)=-4+sqrt(x+3)#

*Here,
#f(x)=-4+sqrt(x+3)#
If we substitute the value of #x# less than#-3#,the value of equation will be indefinable. *

So,Domain#RR={x:x inRR,x>=(-3)}#

Again, for the value of domain set, the value of range set will be greater than or equal -4

So,Range#RR={y:y inRR,y>=(-4)}##color(brown)((Ans.))#