# How do you find the domain and range of f(x) =sqrt(36-x^2)?

Mar 26, 2018

The domain is $- 6 \le x \le 6$
in interval form: $\left[- 6 , 6\right]$

#### Explanation:

The square roots are only defined when the expression under the square root is non-negative.
This function is defined when: $36 - {x}^{2} \ge 0$
${x}^{2} \le 36$
$\left\mid x \right\mid \le 6$
$- 6 \le x \le 6$