# How do you find the domain and range of f(x) = sqrt{Inx}?

There is no x-intercept. Range $: f > 0$. Domain : $x > 1$. See the illustrative graph.
To make f real, $x > 1$.
As $x \to {1}_{+} , f \to 0$ and as $x \to \infty , y \to \infty$.