How do you find the domain and range of #f(x) =sqrt(x-2)#?

1 Answer
Mar 11, 2018

Answer:

Domain #in [2,oo)#

Range #in [0,oo)#

Explanation:

graph{sqrt(x-2 [-10, 10, -5, 5]}

Simply draw out the function.

The standard root function is:

#y=a*sqrt((x-h)) +k#

where #x-h>=0#

In a square root function, the number inside the root sign CANNOT be #<0#

#x-2>=0#

#x>=2#

∴ Domain #in [2,oo)#

As for range, there is no K value in the function we were given
∴ the range begins at 0 to infinity.

Range #in [0,oo)#