# How do you find the domain and range of f(x) = (x)/(sqrt{x - 4})?

Jun 17, 2018

$x > 4$ and #y>=4

#### Explanation:

Since we have a square root in the denominator we get

$x > 4$

for

$\frac{x}{\sqrt{x - 4}}$we get

$\frac{x}{\sqrt{x - 4}} \ge 4$
this is true, since we get

${\left(x - 4\right)}^{2} \ge 0$