# How do you find the domain and range of #root3( (x^2-x-12))#?

##### 1 Answer

Aug 27, 2017

#### Answer:

Domain:

Range:

#### Explanation:

Given:

#f(x) = root(3)(x^2-x-12)#

We can convert the quadratic radicand into vertex form by completing the square:

#x^2-x-12 = x^2-2(1/2)x+(1/2)^2-(1/2)^2-12#

#color(white)(x^2-x-12) = (x-1/2)^2-(1/4+48/4)#

#color(white)(x^2-x-12) = (x-1/2)^2-49/4#

So the minimum value

Then:

#f(1/2) = root(3)(-49/4) = -root(3)(98/8) = -root(3)(98)/2#

Hence the range of

Its domain is the whole of