How do you find the domain and range of #sqrt(1-sinx) #?

1 Answer
Mar 28, 2016

Answer:

With a radical expression we have to make sure the argument is never negative.

Explanation:

Whatever value #x# takes #sinx# will be between #-1and+1#
So the argument (#1-sinx#) will between #0and+2#
Conclusion: the domain is unlimited #(-oo,+oo)#

The range falls between #sqrt0and sqrt2# inclusive (see above)
Or #[0,sqrt2]#