How do you find the domain and range of sqrt(2x - 3)?

Jul 3, 2016

Hi
For the domain: $2 x - 3 \ge 0$
This term must be greater than, or equal to zero
as it is under a root.
and hence

$2 x \ge 3 \Rightarrow x \ge \frac{3}{2}$

As we have 'equal to', we will use a closed bracket [

Hence the domain will be [3/2,infinity)

Infinity will be in open bracket ).