# How do you find the domain and range of #sqrt(2x - 3)#?

##### 1 Answer

Jul 3, 2016

Hi

For the domain:

This term must be greater than, or equal to zero

as it is under a root.

and hence

As we have 'equal to', we will use a closed bracket [

Hence the domain will be [3/2,infinity)

Infinity will be in open bracket ).