# How do you find the domain and range of sqrt(8-x)?

Mar 2, 2017

Domain : $x \in \left(- \infty , 8\right)$
Range : $y \in \left(0 , \infty\right)$

#### Explanation:

For Domain,

$8 - x \ge 0$

$x \le 8$

Domain : $x \in \left(- \infty , 8\right)$

For Range,

$y = \sqrt{8 - x}$

Range : $y \in \left(0 , \infty\right)$