How do you find the domain and range of #sqrt(x^2 - 9)#?

1 Answer
Jul 4, 2017

Answer:

Domain = #x#
Range = #x>=3#

Explanation:

The domain is just the input, the variable=s) being changed. In thus case it is just #x#.

The range is the set of values of #x# which can plotted onto a graph. The lowest possible value for #y# is 0. So, #0=sqrt(x^2-9)#, #0=x^2-9#, #9=x^2#, #x=sqrt(9)=3#. #sqrt(3^2-9)=sqrt(9-9)=sqrt(0)=0#.