# How do you find the domain and range of #(x^2-x-12)^-(1/4)#?

##### 1 Answer

Aug 23, 2017

#### Answer:

See explanation.

#### Explanation:

The function can be written as:

#f(x)=1/(root(4)(x^2-x-12))#

To find the **domain** of rhis function we have to think of the set of arguments (

This function is defined for those values of

#x^2-x-12 >0#

graph{x^2-x-12 [-32.48, 32.47, -16.24, 16.24]}

From the graph we can see that the domain is:

To find the range we have to analyze the end behaviour of the function.

If

If