How do you find the domain and range of #y= 1/sqrtx#?

1 Answer
Mar 28, 2016

Answer:

Domain (Possible value of x) is any positive real number for #x>0#
Range (Possible value of y) is any positive real number except for #x=0#

Explanation:

Domain (Possible value of x) is any positive real number for #x>0#
as square root of negative number is an imaginay number
Range (Possible value of y) is any positive real number except for #x=0# ; which is meaningless at #x=0#