# How do you find the domain and range of #y = 1/(x^2 - 2)#?

##### 1 Answer

Nov 6, 2017

#### Answer:

**Domain:**

**Range:**

#### Explanation:

if denominator is zero.So function is undefined at

and at

expressed as

Range: Any real number of

Range:

graph{1/(x^2-2) [-10, 10, -5, 5]} [Ans]