# How do you find the domain and range of #y=3x^2+2x+1#?

##### 2 Answers

#### Answer:

Since this is a quadratic equation, the domain is ]

#### Explanation:

For the range, one possible method is to express the equation in vertex form, which gives the coordinates of the minimum point. The y-coordinate of the minimum point would give you the smallest value of the range, and the largest value y can take should be

#### Answer:

Domain:

#### Explanation:

Hence the domain of

Since the coefficient of

Since

This can be seen by the graph of

graph{3x^2 +2x +1 [-5.7, 5.4, -0.846, 4.704]}