How do you find the domain and range of #y=5/(x-1)#?

1 Answer
Dec 24, 2016

Answer:

The domain is #=RR-{1}#
The range is #=RR-{0}#

Explanation:

As you cannot divide by #0#, #=>#, #x!=1#

Therefore,

The domain of #x# is #D_x=RR-{1}#

The limit of #y# as #x->oo# is

#lim_(x->-oo)y=lim_(x->-oo)5/x=0^(-)#

#lim_(x->+oo)y=lim_(x->+oo)5/x=0^(+)#

There is a horizontal asymptote at #y=0#

Therefore,

The range is #R_y =RR-{0}#