How do you find the domain and range of #y = sqrt(x - 1)#?

1 Answer
Mar 21, 2018

Answer:

Domain- #1<=x<##prop#
Range- #0<=y<##prop#

Explanation:

#x# cannot be #<1#, because if #x<1#, there would be a negative under the radical, which cannot exist in the real number system. So #x# can be anywhere from #1# to#prop#.

Since #x# must be at least 1, the value of #y# can range from #sqrt0# #=0#, to #sqrt# of any value #>x#, which makes the limit of the range #prop#.