# How do you find the domain and range of y=sqrt(x-2)?

The domain is $x - 2 \ge 0 \implies x \ge 2$ hence ${D}_{f} = \left[2 , + \infty\right)$ and the range is $y = \sqrt{x - 2} \ge 0 \implies y \ge 0$ hence ${R}_{f} = \left[0 , + \infty\right)$