# How do you find the domain and range of y=sqrt(x-4)?

Aug 17, 2015

Since the argument must be non-negative $x \ge 4$.
Since there is no upper limit the domain of $x$ is $\left[4 , \infty\right)$
When $x = 4 \to y = 0$.
Again there is no upper limit, so the range of $y$ is $\left[0 , \infty\right)$