How do you find the domain and range of #y = sqrt(x+8)#?
Let's take a look at the equation first.
For the domain, we're interested in the values of x that give a "valid result".
In other words, we're looking for values of x that won't "break" the equation.
We notice that
Therefore, we can set this up.
subtract 8 from both sides to get,
Now, for the range.
We know that the square root of a number cannot be negative. This is the same for function such as
It's worth noting here that the square root symbol is used to indicate only the positive root. For example,