How do you find the domain for #h(c)=c/(c^2+25)#?

1 Answer
Jun 23, 2017

Answer:

The domain is #(-oo,oo)#.

Explanation:

Our only restrictions to the domain will occur when the denominator of the fraction equals #0#.

We can try to find the domain restrictions then by:

#c^2+25=0" "=>" "c^2=-25#

This has no real solutions (we can't take the square root of a negative number), so there are no restrictions on the domain.

Thus, the domain is #(-oo,oo)#.