# How do you find the domain for h(x)=(x+2)/sqrt(x^2 - 7)?

Anything that makes the denominator $= 0$ is forbidden.
Also, because of the root, ${x}^{2} - 7$ must be non-negative.
Together: ${x}^{2} - 7 > 0 \to {x}^{2} > 7$
This means that either $x > \sqrt{7}$ or $x < - \sqrt{7}$
See graph ($\sqrt{7} \approx 2.65$)