# How do you find the domain of f(x) = 2 / sqrt(3x-2)?

Jun 17, 2018

$x > \frac{2}{3}$

#### Explanation:

Since we have a square root in the denominator we get

$x > \frac{2}{3}$

Jun 17, 2018

$x \in \mathbb{R} , x > \frac{2}{3}$

#### Explanation:

$\text{the denominator of f(x) cannot be zero as this would}$
$\text{makef(x) undefined}$

$\text{we require } 3 x - 2 > 0 \Rightarrow x > \frac{2}{3}$

$\text{domain "(2/3,oo)larrcolor(blue)"in interval notation}$
graph{2/(sqrt(3x-2)) [-14.24, 14.24, -7.12, 7.12]}