# How do you find the domain of #f(x) = 2 / sqrt(3x-2)#?

##### 2 Answers

Jun 17, 2018

#### Explanation:

Since we have a square root in the denominator we get

Jun 17, 2018

#### Explanation:

#"the denominator of f(x) cannot be zero as this would"#

#"makef(x) undefined"#

#"we require "3x-2>0rArrx>2/3#

#"domain "(2/3,oo)larrcolor(blue)"in interval notation"#

graph{2/(sqrt(3x-2)) [-14.24, 14.24, -7.12, 7.12]}