How do you find the domain of #f(x) = 2 / sqrt(3x-2)#?

2 Answers
Jun 17, 2018

Answer:

#x>2/3#

Explanation:

Since we have a square root in the denominator we get

#x>2/3#

Jun 17, 2018

Answer:

#x inRR,x>2/3#

Explanation:

#"the denominator of f(x) cannot be zero as this would"#
#"makef(x) undefined"#

#"we require "3x-2>0rArrx>2/3#

#"domain "(2/3,oo)larrcolor(blue)"in interval notation"#
graph{2/(sqrt(3x-2)) [-14.24, 14.24, -7.12, 7.12]}