Question

How do you find the domain of `f(x) = 2 / sqrt(3x-2)`?

Answer 1

`x>2/3`

Explanation:

Since we have a square root in the denominator we get

`x>2/3`

Answer 2

`x inRR,x>2/3`

Explanation:

`"the denominator of f(x) cannot be zero as this would"`
`"makef(x) undefined"`

`"we require "3x-2>0rArrx>2/3`

`"domain "(2/3,oo)larrcolor(blue)"in interval notation"`
graph{2/(sqrt(3x-2)) [-14.24, 14.24, -7.12, 7.12]}