Question

How do you find the domain of `f(x) =2sqrt(3x + 4) - 5`?

Answer 1

Domain: `x>= -4/3` , Range: `f(x) >= -5`

Explanation:

Domain (possible value of x) : `3x+4 >=0 or 3x >= -4 or x>= -4/3` since under root can not be negative number.

Range (possible value of f(x)) : `f(x)> =2*0 -5 >=-5`
Domain: `x>= -4/3` , Range: `f(x) >=-5`
graph{2(3x+4)^0.5-5 [-20, 20, -10, 10]} [Ans]