How do you find the domain of f(x) =2sqrt(3x + 4) - 5?

Domain: $x \ge - \frac{4}{3}$ , Range: $f \left(x\right) \ge - 5$
Domain (possible value of x) : $3 x + 4 \ge 0 \mathmr{and} 3 x \ge - 4 \mathmr{and} x \ge - \frac{4}{3}$ since under root can not be negative number.
Range (possible value of f(x)) : $f \left(x\right) > = 2 \cdot 0 - 5 \ge - 5$
Domain: $x \ge - \frac{4}{3}$ , Range: $f \left(x\right) \ge - 5$