How do you find the domain of #f(x)=(2x^2)/(x^2-9)#?

1 Answer
May 20, 2017

Answer:

#x inRR,x!=+-3#

Explanation:

The domain is defined for all values of x except values that make the denominator of f(x) equal to zero as this would make f(x) #color(blue)"undefined"# Equating the denominator to zero and solving gives the values that x cannot be.

#"solve " x^2-9=0rArr(x-3)(x+3)=0#

#rArrx=+-3larrcolor(red)" excluded values"#

#rArr"domain is " x inRR,x!=+-3#