How do you find the domain of #f(x)=(2x)/((x-2)(x+3))#?

2 Answers
Jul 18, 2017

Answer:

The denominatos can't be zero.

Explanation:

The only contraint is : #(x-2)(x+3)!=0 iff x!=2 and x!=-3#

so the domain is then #D=x in RR-{-3,2}#

Jul 18, 2017

Answer:

#x inRR,x!=-3,2#

Explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be.

#"solve " (x-2)(x+3)=0#

#rArrx=-3" and " x=2larrcolor(red)" are excluded values"#

#"domain is " x inRR,x!=-3,2#