How do you find the domain of #f(x) =3sqrt(6x + 42)#?
1 Answer
Mar 23, 2018
Explanation:
#"the domain is determined by the radical"#
#"that is "#
#6x+42>=0rArrx>=-7#
#rArr" domain is "[-7,+oo)#
graph{3sqrt(6x+42) [-10, 10, -5, 5]}