# How do you find the domain of f(x) =3sqrt(6x + 42)?

Mar 23, 2018

$\left[- 7 , + \infty\right)$

#### Explanation:

$\text{the domain is determined by the radical}$

$\text{that is }$

$6 x + 42 \ge 0 \Rightarrow x \ge - 7$

$\Rightarrow \text{ domain is } \left[- 7 , + \infty\right)$
graph{3sqrt(6x+42) [-10, 10, -5, 5]}