How do you find the domain of #f(x)=(3x+1)/(sqrt (x^2+x-2))#?
This question just happens to look so deadly, but isn't actually hard at all
Remember, in a fraction, in the form of
Thus, the denominator can never be 0
In the denominator here, if the value of x ever becomes 1, then, the value of the denominator equals to a 0, thus not satisfying the principle
Therefore, the denominator can have any value, but 0, and to reach 0, the value of x must be 1, so therefore, x should never be equal to 1, and other than that, the value of x can be anything