# How do you find the domain of f(x)=(3x+1)/(sqrt (x^2+x-2))?

May 4, 2016

$\left\{x \in \mathbb{R} | x \ne 1\right\}$

#### Explanation:

This question just happens to look so deadly, but isn't actually hard at all

Remember, in a fraction, in the form of $p / q , q \ne 0$
Thus, the denominator can never be 0
In the denominator here, if the value of x ever becomes 1, then, the value of the denominator equals to a 0, thus not satisfying the principle

Therefore, the denominator can have any value, but 0, and to reach 0, the value of x must be 1, so therefore, x should never be equal to 1, and other than that, the value of x can be anything