# How do you find the domain of f(x) = x^2 + 5?

Jul 16, 2017

See below.

#### Explanation:

Ignoring the $5$, we know that ${x}^{2}$ has a minimum value of $0$, which is achieved when $x = 0$.

When $x$ approaches $- \infty$, the range remains real (it approaches $\infty$).

When $x$ approaches $\infty$, the range remains real (it approaches $\infty$).

Thus, the domain of this function is $\left(- \infty , \infty\right)$.