# How do you find the domain of f(x) =( x - 2) / (x^2- 16)?

Nov 5, 2015

$\left\{x \in \mathbb{R} : x \ne - 4 \mathmr{and} x \ne 4\right\}$

#### Explanation:

Set the denominator equal to 0.

${x}^{2} - 16 = 0$

Solve for x.

// add 16 to both sides

${x}^{2} = 16$

// root both sides

$x = 4 , - 4$

The domain is 4, -4 as the denominator cannot be 0. So therefore, the domain can be stated as $\left\{x \in \mathbb{R} : x \ne - 4 \mathmr{and} x \ne 4\right\}$