How do you find the domain of #f(x) =( x - 2) / (x^2- 16)#?

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Answer 1 · 2015-11-05T18:27:46

#{x in RR : x!= -4 and x!= 4} #

Set the denominator equal to 0.

#x^2 - 16 = 0#

Solve for x.

// add 16 to both sides

#x^2 = 16#

// root both sides

#x = 4, -4#

The domain is 4, -4 as the denominator cannot be 0. So therefore, the domain can be stated as #{x in RR : x!= -4 and x!= 4} #