How do you find the domain of #f(x) = (x+2)/(x-3) #?

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Answer 1 · 2016-06-07T09:34:28

Domain = #{x:xepsilon RR, x != 3}#

This reads as "The domain is the set of all elements x, such that x is an element of the set of Real numbers, but x is not equal to 3"

The domain is the set of all the possible x-values.

Looking at the numerator, any #x-#value can be used.

However, in a fraction the denominator may not be equal to 0.

In this case is #x = 3#, then the denominator will be 0, so #x# may not be 3, but any other value would be fine. We write it as:

Domain = #{x:xepsilon RR, x != 3}#

This reads as "The domain is the set of all elements x, such that x is an element of the set of Real numbers, but x is not equal to 3"