# How do you find the domain of f(x)=(x+5)^(1/2)?

$f \left(x\right) = \sqrt{x + 5}$
A square root is $\ge 0$
so $x + 5 \ge 0$
$x \ge - 5 g r a p h \left\{\sqrt{x + 5} \left[- 10 , 10 , - 5 , 5\right]\right\}$