How do you find the domain of #f(x)=x/(6x^2+13x-5)#?

1 Answer
Jun 20, 2016

Answer:

Domain (value of x) is any real value except #x = 1/3 or x = -2/5#

Explanation:

Domain is the value of x in the function. Here the denomintor must not be zero. #6x^2+13x-5 !=0 or 6x^2+15x-2x-5 != 0 or 3x(2x+5)-1(2x+5) !=0 or (3x-1)(2x+5) !=0 or x !=1/3 and x !=-5/2 :.#Domain (value of x) is any real value except #x = 1/3 or x = -2/5# [Ans]