How do you find the domain of f(x)=x/(x^2+1)?

Apr 16, 2017

The domain is $= \mathbb{R}$

Explanation:

The denominator is $\left({x}^{2} + 1\right)$

$\forall x \in \mathbb{R} , \left({x}^{2} + 1\right) > 0$

So, the domain of $f \left(x\right)$ is

${D}_{f} \left(x\right) = \mathbb{R}$

graph{x/(x^2+1) [-10, 10, -5, 5]}