How do you find the domain of #g(x) = 1/(3-x)^(1/2)#? Algebra Expressions, Equations, and Functions Domain and Range of a Function 1 Answer Gerardina C. Jul 4, 2017 #x<3# Explanation: Since #f(x)^(1/2)=sqrtf(x)#, we get #1/(3-x)^(1/2)=1/(sqrt(3-x)# Then the domain is: #3-x>=0 and 3-x!=0# that's #3-x>0# #x<3# Answer link Related questions How do you determine if (-1, 4), (2, 8), (-1, 5) is a function? What is the domain for #f(x)=2x-4#? What is the domain and range for (3,1), (1,-4), and (2, 8)? What is the domain and range of a linear function? Is domain the independent or dependent variable? How do you find the domain and range of a function in interval notation? How do you find domain and range of a rational function? How do you find domain and range of a quadratic function? How do you determine the domain and range of a function? What is Domain and Range of a Function? See all questions in Domain and Range of a Function Impact of this question 1811 views around the world You can reuse this answer Creative Commons License