# How do you find the domain of g(x) = sqrt(x^2 - 9)?

All real numbers x: x$\le$-3 or x$\ge$3.
Domain would be all real numbers x such that ${x}^{2} - 9$ is $\ge$0. On solving this inequality, it would be ${x}^{2}$ $\ge$9,
x $\ge 3$, or -x$\ge$3 or x $\le$-3