# How do you find the domain of g(x)= x^2/(1-x^2)?

All real values of $x$ except $\pm 1$
The function $g \left(x\right)$ is undefined if the denominator becomes $0$
i.e $1 - {x}^{2} = 0$
so ${x}^{2} = 1$ , $x = \pm 1$