# How do you find the domain of h(x)= 1/(x+1)?

Apr 22, 2018

All real numbers excluding $x = - 1$; $\left(- \infty , - 1\right) U \left(- 1 , \infty\right)$

#### Explanation:

The domain includes all values of $x$ for which $h \left(x\right)$ exists.

For rational functions (such as this one), the domain doesn't exist for values of $x$ which cause division by $0.$ So, let's determine which values of $x$ cause the denominator to equal $0 :$

$x + 1 = 0$

$x = - 1$.

Then, the domain is all values of $x$ excluding $x = - 1.$ In interval notation,

$\left(- \infty , - 1\right) U \left(- 1 , \infty\right)$