# How do you find the domain of sqrt(9-x)?

Jun 12, 2017

Domain: $x \le 9$

#### Explanation:

Since we have a sqrt, we know that this sqrt must be greater than or equal to $0$.

$\sqrt{9 - x} \ge 0$

$9 - x \ge 0$

$9 \ge x$

$x \le 9$