How do you find the domain of # sqrt(x^2+2x-24)#?

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Answer 1 · 2017-05-24T14:29:44

the domain is: #]-oo,-6]uu[4,+oo[#

You cannot have negative values under a square root, then it must be:

#x^2+2x-24>=0#

The zeros of the polynomial #x^2+2x-24# are

#x=-1+-sqrt(1+24)=-1+-5#

that are #x=-6# and #x=4#

then the domain is:

#]-oo,-6]uu[4,+oo[#