How do you find the domain of #sqrt(x+4)#?

2 Answers
Mar 26, 2018

Answer:

The domain is #x >= 4 #

Explanation:

Since square roots are only defined when the expression under the square root is non-negative, to find the domain we set the expression under the square root greater than or equal to zero:

#x - 4 >= 0#
#x >= 4 #

Mar 26, 2018

Answer:

#[-4,oo)#

Explanation:

Firstly you know that there can't be a negative under a square root #sqrt(-1)# any negative leads to the function being undefined

So when #x+4<0# i.e. it is lower than zero you know there is no domain

So when #x+4>=0# the domain exists so it eixsts when #x>=-4#

So the domain is #[-4,oo)#