How do you find the domain of # sqrt(x + 5) #?

1 Answer
Mar 13, 2018

Answer:

#x in RR,x>=-5#

Explanation:

#"the expression inside the radical must be greater than"#
#"or equal to zero"#

#"solve "x+5>=0" for domain"#

#"subtract 5 from both sides"#

#xcancel(+5)cancel(-5)>=0-5#

#rArrx>=-5#

#"domain is "x in RR,x>=-5#

#[-5,+oo)larrcolor(blue)"in interval notation"#
graph{sqrt(x+5) [-10, 10, -5, 5]}