# How do you find the domain of the function f(x) = (4x^3 − 1) / (x^2 + 4x − 12)?

Anything that makes the denominator equal to $0$ is forbidden
So we solve ${x}^{2} + 4 x - 12 = 0$, first we factorise
$\implies \left(x - 2\right) \left(x + 6\right) = 0 \implies x = 2 \mathmr{and} x = - 6$
$x \ne 2$ and $x \ne - 6$